The resultant of vector A and vector B makes an angle a with vector A and β with vector B, (a) α < β

(c) α &lt; β if A &gt;β​

(c) C must be greater than I A —B I

Answer is (a) π  \(\vec{A}\times\vec{B}\) = AB sinθ \(\hat{n}\) \(\vec{B}\times\vec{A}\) = AB sin(2π - θ)\(\hat{n}\) AB sinθ \(\hat{n}\) = AB sin(2π - θ)\(\hat{n}\) θ = 2π - θ 2θ = 2π θ = π 

(a) : vector a = 8vector b vector c = - 7vector b vector a and vector b are parallel and vector b and vector c are antiparallel. Thus vector a and vector c are...

(b) It is possible to have | vector C | &lt; | vector A | and | vector C | &lt; | vector B | 

(c) C must be greater than | A - B|  

(c) A is correct but B is wrong

Thanks mam And big thanks to this app that solves most of the jee question

A +B=? How?

vector a || vector b ⇒ vector a × vector b = vector 0 ⇒ i(–9 – 3λ) + k(2λ + 6) = vector 0 ⇒ λ = – 3.