Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is

(a) 1/9 

(b) 2/9

(c) 7/9 

(d) 8/9.

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1 Answers

(a) : No. of houses = 3 = No. of favourable cases
No. of applicants = 3,
∴ Total number of events = 33
(because each candidate can apply by 3 ways)
Required probability = 3/33 = 1/9.

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