It is found that if a neutron suffers an elastic collinear collision with deuterium at rest, fractional loss of its energy is pd ; while for its similar collision with carbon nucleus at rest, fractional loss of energy is pc. The values of pd and pc are respectively :
(1) (.28, .89) 

(2) (0, 0) 

(3) (0, 1) 

(4) (.89, .28)

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2 Answers

Collision is elastic here so I think there is no lose
 of kinetic energy

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Coefficient of restitution (e)
e= V2- V1/U1-U2
here collision is elastic so
E= 1
V2- V1/U1-U2 = 1
And U2 =0
Hence
V2-V1= U

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