A solution contains 2.675g of CoCl6NH3 (molar mass = 267.5g mol–1) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78g of AgCl (molar mass = 143.5g mol-1). The formula of the complex is (At. mass of Ag = 108u) 

(a) [CoCl(NH3)5]Cl2 

(b) [Co(NH3)6]Cl3 

(c) [CoCl2(NH3)4]Cl 

(d) [CoCl3(NH3)3]


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(b) : No. of moles of CoCl3·6NH3 = (2.675)/(267.5) = 0.01

No. of moles of AgCl = (4.78)/(143.5) = 0.03.

Since 0.01moles of the complex CoCl3·6NH3 gives 0.03moles of AgCl on treatment with AgNO3, it implies that 3 chloride ions are ionisable, in the complex. Thus, the formula of the complex is [Co(NH3)6]Cl3.

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