The number of delectrons retained in Fe^2+ (At. no. Fe = 26) ions is
The number of delectrons retained in Fe2+ (At. no. Fe = 26) ions is
(a) 3
(b) 4
(c) 5
(d) 6.
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(d) : 26Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2
Fe++ = 1s2 2s2 2p6 3s2 3p6 3d6
The number of d electrons retained in Fe2+ = 6.
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