The formation of the oxide ion O2–(g) requires first an exothermic and then an endothermic step as shown below.
O(g) + e = O(g) ; ΔH° = –142kJ mol–1

O(g) + e = O2–(g) ; ΔH° = 844kJ mol–1

This is because
(a) oxygen is more electronegative
(b) oxygen has high electron affinity
(c) O ion will tend to resist the addition of another electron
(d) O ion has comparatively larger size than oxygen atom.

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1 Answers

(c) :- The addition of second electron in an atom or ion is always endothermic.

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