If x, v and a denote the displacement, the velocity.

Question

If x, v and a denote the displacement, the velocity.

If x, v and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T, then, which of the following does not change with time?

(a) a²T²+ 4π²v²

(b) aT/x

(c) aT + 2πv

(d) aT/v

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

(b) : For a simple harmonic motion,
acceleration, a = –ω²x where ω is a constant = 2π/T.

a = - 4π²/T². x ⇒ aT/x = - 4π²/T.

The period of oscillation T is a constant.
∴ aT/x is a constant.

4 views Answered 2023-02-05 15:29