Wavelength of light used in an optical instrument are λ1 = 4000Å and λ2 = 5000Å,
Wavelength of light used in an optical instrument are λ1 = 4000Å and λ2 = 5000Å, then ratio of their respective resolving powers (corresponding to λ1 and λ2 ) is
(a) 16 : 25
(b) 9 : 1
(c) 4 : 5
(d) 5 : 4.
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(d) : Resolving power is proportional to λ–1
Therefore, (R.P.for λ1)/(R.P. for λ2) = λ1/λ2 = (5000)/(4000) =5/4.
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