The acceleration of the moon just before it strikes the earth in the previous question is
The acceleration of the moon just before it strikes the earth in the previous question is
(a) 10 m/s2
(b) 0.0027 m/s2
(c) 6.4 m/s2
(d) 5.0 m/s2
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(c) 6.4m/s2 .
Explanation:
When the moon strikes the earth its center is R/4 above the surface of the earth. So the acceleration of the moon will be calculated at R+R/4 = 5R/4 away from the center of the earth. Since the acceleration is inversely proportional to the square of the distance, the acceleration of the moon at the time of strike
= g*{R/(5R/4)}² = g*(4/5)² = 16g/25 =160/25 =6.4 m/s².
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