Two springs A and B(kA = 2kB) are stretched by applying forces of equal magnitudes at the four ends.
Two springs A and B(kA = 2kB) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in A is E, that in B is
(a) E/2 (b) 2E (c) E (d) E/4.
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(b) 2E.
Explanation:-
Since (kA = 2kB) it means for the same force xB = 2xA . So if energy stored in spring A = E = F.xA Energy stored in spring B = F.xB =F.2xA =2E
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