An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term?
An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.
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Solution: 12 = a + 2d
106 = a + 49d
So, 106-12 = 47d
Or, 94 = 47d
Or, d = 2
Hence, a = 8
And, n29 = 8 + 28x2 = 64
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