(i) What is observed when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube?
(ii) What type of reaction is this?
(iii) Write a balanced chemical equation to represent the above reaction.


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(i) A yellow precipitate of lead iodide (PbI2) is formed.
(ii) Precipitation reaction/Double displacement reaction.
(iii) Pb(NO3)2(aq) + 2KI(aq) ------> PbI2(s) +   2KNO3 (aq)
Lead nitrate           Potassium iodide    Lead iodide     Potassium nitrate

                                                              (Yellow ppt.)     

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(i) Yellow coloured precipitate is formed due to formation of lead iodide. 

(ii) It is a double displacement reaction. 

(iii) 2KI + Pb(NO3)2 → 2KNO3 + Pbl2

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