(i) What is observed when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube?
(ii) What type of reaction is this?
(iii) Write a balanced chemical equation to represent the above reaction.
(i) A yellow precipitate of lead iodide (PbI2) is formed.
(ii) Precipitation reaction/Double displacement reaction.
(iii) Pb(NO3)2(aq) + 2KI(aq) ------> PbI2(s) + 2KNO3 (aq)
Lead nitrate Potassium iodide Lead iodide Potassium nitrate
(i) When silver nitrate solution is added to sodium chloride solution, a white precipitate of silver chloride is formed along with sodium nitrate solution.
AgNO3(aq)+ NaCl(aq) --------> AgCl(s) + NaNO3(aq)
...
In test tube ‘A’ – blue black colour because of presence of starch. In test tube ‘B’ – colour of iodine will not change because of digestion of starch into...
The correct answer is (b) 10√2 cm
Explanation:
When the tube is inclined, the vertical rise remains the same. So the water in the inclined tube rises to 10*sec45° =10√2 cm.