What product is obtained when ethyl benzene is oxidized with alkaline KMnO4 ?

In KMnO4        K = +1,       Mn = +7,     O = –2  In K2Cr2O7     K = +1,       Cr = +6,       O...

They are better reducing agent than C and CO. 

Alkali and alkaline earth metals cannot be obtained by chemical reduction methods because they are very strong reducing agent and highly reactive metals. Because of this they can not be reduced by any other substance very easily.

CH3- is a ERG while –NO2 is a EWG .Therefore electron density is more in toluene than in benzene and the electron density in m-dinitrobenzene will be less than in...

[Hint : KMnO4, since Mn is showing maximum oxidation state of + 7.]

(B) oxidising agent

H2S + Cl2 → S + 2HCl 1) H2S is oxidised to S by losing hydrogen atoms. 2) Cl2 is reduced to HCl by gaining hydrogen atoms. 3) The substance which gets oxidised is called reducing...

(c) In KMnO4 manganese is already present in its highest possible oxidation state i.e. +7.So no further oxidation is possible.

L TPL AP = TP/L MP = TPn -TPn - 1 0 0 0 - 1 15 15 15 2 35 17.5 20 3 50 16.67 15 4 40 10 -10 5 48 9.6 -8

L APL TPL = AP x L MPL = TPn - TPn -1 1 2 2 x 1 = 2 2 2 3 3 x 2 = 6 6 - 2 = 4 3 4 4 x 3 = 12 12 - 6 = 6 4 4.25 4.25...