Action of soap is due to emulsification and micelle formation. Comment.
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Where is emulsification of fat completed in the human body?
Emulsification of the fats in human body occurs in small intestine
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Where is emulsification of fat completed in the human body?
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Explain the formation of scum when hard water is treated with soap.
Hard water contains salts of calcium and magnesium. When soap molecule comes in contact with these salts it forms a curdy white precipitate (compound insoluble in water) called scum. Soap +...
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Action of soap is due to emulsification and micelle formation. Comment.
The cleansing action of soap is due to emulsification and micelle formation. Soaps are basically sodium and potassium salts of long chain fatty acids, R-COO-Na+. The end of the molecule...
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In the soap micelles, _______. (A) the ionic end of soap is on the surface of the cluster while the carbon chain is in the interior of the cluster
(A) the ionic end of soap is on the surface of the cluster while the carbon chain is in the interior of the cluster
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The cleansing action of soap is more in soft water as it
(B) does not have salts in it
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A soap solution appears cloudy because (A) soap micelles absorb light (B) soap micelles precipitate out
(D) soap micelles scatter light
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Why does micelle formation take place when soap is added to water? Will a micelle be formed in other solvents such as ethanol also,
i. A soap molecule has two ends having different properties. The ionic end of the molecule is hydrophilic and it dissolves in water, while the hydrocarbon ‘tail’ of the molecule...
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Air is pushed into a soap , bubble of radius r to double its radius. If the surface tension of the soap solution is S,
The correct answer is (d) 24πr2S. Explanation: The surface tension S is equal to surface energy per unit area, S = U/A →U = SA The total area of the soap bubble =2*4πr² =8πr² The...
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The excess pressure inside a soap bubble is twice the excess pressure inside a second soap bubble.
The correct answer is (d) 0125. Explanation: Let the radius of the first soap bubble = r, Excess pressure inside P = 4S/r Let the radius of the second soap bubble = r' Excess pressure...
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