Consult the table of standard electrode potentials and suggest three substances that can oxidise ferrous ions under suitable conditions.

(i). Sodium (Na) is oxidised as it gains oxygen and oxygen gets reduced.  (ii). Copper oxide (CuO) is reduced to copper (Cu) while hydrogen (H2) gets oxidised to water (H2O).

Here is Reaction with Balance 10FeC2O4 + 6KMnO4 + 24H2SO4 ----> 3K2SO4+ 6MnSO4 +  5Fe2(SO4)3 + 24H2O + 20CO2 So we see that  6 moles of KMnO4 is required to oxidize 10 moles of  FeC2O4  Then, 1 mole of FeC2O4 would be...

The correct conditions is q = 0. So option (iii) is correct.

Answer: We have The lower the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg <...

E0cell  =  E0 cathode  −  E0 anode

SHE, whose electrode potential is taken as zero.

The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials increase in the order of K+/K < Mg2+/Mg < Cr3+/Cr < Hg2+/Hg < Ag+/Ag.  Hence,...

(i) In this reaction, sodium (Na) is changed into sodium oxide (Na2O). This is the addition of oxygen to sodittm. Since addition of oxygen is called oxidation, therefore, the substance...

(a) :         A       B         C E°red +0.5V –3.0V –1.2V More is the value of reduction potential, more is the tendency to get reduced, i.e....

Iron absorbed by plants is Ferric