For a morning walk, three persons steps off together. Their steps measure 80 cm, 85 cm and 90 cm respectively.

The minimum distance that they all three should walk will be the L.C.M. of 40, 45, 50. Since  40=2×2×2×5  45=3×3×5  50=2×5×5 ∴ L.C.M. of 40, 45 and 50 = 2×2×2×3×3×5×5= 1800cm = 18m

Solution: 9 = 3 x 3 = 32 12 = 2 x 2 x 3 = 22 x 3 15 = 3 x 5 => LCM (9, 12, 15) = 22 x 32 x 5 = 180 => the bells will toll together...

Solution: Since, the three persons start walking together. Therefore, The minimum distance covered by each of them in complete steps = LCM of the measures of their steps = LCM (40, 42, 45) 40...

Solution: 90°, as they add up to 180°

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