Write the HCF of smallest composite number and smallest prime number.
Solution : i) 26 and 91 26=2×13×1(expressing as product of it’s prime factors) 91=7×13×1(expressing as product of it’s prime factors) So, LCM(26,91)=2×7×13×1=182 HCF(26,91)=13×1=13 Verification: LCM×HCF=13×182=2366 Product of 26 and 91 =2366 Therefore,LCM×HCF=Product of the two numbers . i) 510 and...
1 Answers 1 viewsSolution : i) 12,15 and 21 12=2×2×3 15=5×3 21=7×3 From the above ,HCF(12,15,21)=3and LCM(12,15,21)=420 ii)17,23,and 29 17=17×1 23=23×1 29=29×1 From the above ,HCF(17,23,29)=1and LCM(17,23,29)=11339 iii)8,9 and 25 8=2×2×2 9=3×3 25=5×5 From the above ,HCF(8,9,25)=1and LCM(8,9,25)=1800
1 Answers 1 viewsA = {x: x is a natural number} = {1, 2, 3, 4, 5 …} B ={x: x is an even natural number} = {2, 4, 6, 8 …} C = {x:...
1 Answers 1 viewsAnswer Possible numbers of events on throwing a dice = 6 Numbers on dice = 1,2,3,4,5 and 6 (i) Prime numbers = 2, 3 and 5 Favourable number of events = 3 Probability that it...
1 Answers 1 viewsSolution: 117 = 65 x 1 + 52 65 = 52 x 1 + 13 65 = 13 x 5 + 0 => HCF(65, 117) = 13 Since, HCF(65, 117) = 65m - 117 => 13 = 65m - 117 => 65m...
1 Answers 1 viewsCorrect answer is (B) xy2
1 Answers 1 viewsIt is (B) an irrational number
1 Answers 2 viewsBy applying Euclid’s division lemma (i) 54 = 32 × 1 + 22 Since remainder ≠ 0, apply division lemma on division of 32 and remainder 22. 32 = 22 × 1 +...
1 Answers 1 views3x5x7+7=7(3x5+1)=7x16, which has more than two factors.
1 Answers 1 viewsTotal non-prime numbers from 1 to 10 = 6 Required probability =6/10=3/5
1 Answers 1 views