John placed 10 moles of sulphur molecules (S8) and 5 moles of glucose (C6H12O6) in the two different pans of a physical balance.

Question

John placed 10 moles of sulphur molecules (S8) and 5 moles of glucose (C6H12O6) in the two different pans of a physical balance.

John placed 10 moles of sulphur molecules (S₈) and 5 moles of glucose (C₆H₁₂O₆) in the two different pans of a physical balance. Find which pan of the balance would be heavier, support your answer with calculations.

(Atomic mass: O = 16 u, C = 12 u, H = 1 u, S = 32 u)

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Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

Molecular mass of sulphur molecules (S₈)

= 32 × 8 = 256 gm

Molecular mass of glucose (C₆H₁₂O₆)

=(6 × 12) +( 1 × 12) +( 6 × 16)

= 72 + 12 + 96=180

Weight of 10 moles of S8 =10 × 256 = 2560

Weight of 5 moles of glucose = 5 × 180 = 900

Therefore, 10 moles of sulphur would weigh more.

John placed 10 moles of sulphur molecules (S8) and 5 moles of glucose (C6H12O6) in the two different pans of a physical balance.

1 Answers