Water molecules have hydrogen and oxygen in the ratio of 1: 8 by mass. Find the ratio of number of atoms of elements in water molecules.

It is given that: n(S) = 21, n(T) = 32, n(S ∩ T) = 11  We know that: n (S ∪ T) = n (S) + n (T) – n (S...

It is given that: n(X) = 40, n(X ∪ Y) = 60,  n(X ∩ Y) = 10  We know that:  n(X ∪ Y) = n(X) + n(Y) – n(X ∩ Y)  ∴ 60 = 40...

(c) ozone and oxygen

(c) The two oxygen atoms are isotopes

It is given that the ratio of hydrogen and oxygen by mass to form water is 1:8. Then, the mass of oxygen gas required to react completely with 1g of...

(a) Mass of one mole of oxygen atoms = 16g  Then, mass of 0.2 mole of oxygen atoms = 0.2 × 16g = 3.2g  (b) Mass of one mole of water molecule...

1 mole of oxygen atoms = 6.023×1023 atoms  ∴Number of moles of oxygen atoms =   2.58 ×1024 / 6.022×1023                             ...

(i) Third period Group-1 ,2,13,14, 15, 16, 17, 18 respectively. (ii) Nature of compound: Electrovalent/ionic (iii) Metals-A and B; Non-metals-E, F, G (iv) G/H (v) CG3 (vi) H (vii) A (viii) D

It is given that: n(S) = 21, n(T) = 32, n(S ∩ T) = 11 We know that: n (S ∪ T) = n (S) + n (T) – n (S...

It is given that:  n(X) = 40, n(X ∪ Y) = 60, n(X ∩ Y) = 10  We know that: n(X ∪ Y) = n(X) + n(Y) – n(X ∩ Y)  ∴ 60 = 40...