An artificial is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hrs to revolve around the earth.

Solution: They will be meet again after LCM of both values at the starting point. To get the LCM we have to factorize the number. 18        = 2 × 3 × 3 12...

For hydrogen like atom. En \(\propto\) -\(\frac{Ƶ^2}{n^2}\) En = -k\(\frac{Ƶ^2}{n^2}\) for hydrogen atom- E4 = -k\(\frac{(1)^2}{4^2}\)  E4 = \(\frac{-k}{16}\)  given, E4 = € \(\because\) k = -€ x 16----(1) For Li+2 E1 = \(-\frac{k(3)^2}{1^2}\)  = -k x 9 using equation (1) we get E1 = € x 16 x 9 E1 = 144 €

Gravitational force. This force depends on the product of the masses of the planet and sun and the distance between them. 

(d) The instantaneous acceleration of the earth points towards the sun. Explanation:  Since during the mentioned period in (a) and (b) the earth covers a semi circle and there is a displacement...

(b) The magnitude of the frictional force on the car is greater than mv2/r  (c) The friction coefficient between the ground and the car is not less than α/g.  Explanation:  Since the circular...

(c) IA <IB   Explanation:  Let the density of iron plate be ρ.  Mass of first disc m = πr²tρ  M.I. = IA = ½mr² == ½πr²tρr² = ½πr4tρ  Mass of second disc = M =...

(a) the mass of the satellite EXPLANATION:  If the radius of the orbit = a, then velocity of an earth satellite v = √(GM/a) and the time period T = 2πa/v.   ...

(d) The instantaneous acceleration of the earth points towards the sun. Explanation:  Since during the mentioned period in (a) and (b) the earth covers a semi circle and there is a displacement between original point to...

Since the Pipe is double the size, it will take1/2 time of the time taken by the smaller pipe Therefore 1/2x4 =2 hrs