Draw formulas for the first five members of each homologous series beginning with the following compounds. 

(a) H–COOH 

(b) CH3COCH

(c) H–CH=CH2

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1 Answers

The first five members of each homologous series beginning with the given compounds are shown as follows: 

(a) 

H–COOH : Methanoic acid 

CH3–COOH : Ethanoic acid 

CH3–CH2–COOH : Propanoic acid 

CH3–CH2–CH2–COOH : Butanoic acid 

CH3–CH2–CH2–CH2–COOH : Pentanoic acid 

(b) 

CH3COCH3 : Propanone CH3COCH2CH3

Butanone 

CH3COCH2CH2CH3 : Pentan-2-one 

CH3COCH2CH2CH2CH3 : Hexan-2-one 

CH3COCH2CH2CH2CH2CH3 : Heptan-2-one 

(c) 

H–CH=CH2 : Ethene 

CH3–CH=CH2 : Propene 

CH3–CH2–CH=CH2 : 1-Butene 

CH3–CH2–CH2–CH=CH2 : 1-Pentene 

CH3–CH2–CH2–CH2–CH=CH2 : 1-Hexene 

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