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Solution: In this case, the ladder makes the hypotenuse, the height of top of the ladder is perpendicular and the distance of foot of the ladder from the base of the wall is the base.
So, h = 10 m, p = 8 m and b = ?
From Pythagoras theorem;
b2 = h2 – p2
Or, b2 = 102 – 82
= 100 – 64 = 36
Or, b = 6 m
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In ⊥∆ACB, ∠C = 90°, BC = ?
AC2 + CB2 = AB2
(8)2 + CB2 = (10)2
64 + CB2 = 100
CB2 = 100 – 64
CB2 = 36
∴ CB = 6
∴ Ladder is at a distance of 6m from the base of the wall.
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