If the sum of the zeroes of the quadratic polynomial 3x2 – kx + 6 is 3, find the value of k.
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Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
(i) 6x² + 11x + 5 = 0 6x2 + 11x + 5 = 6x2 + 6x + 5x + 5 = 6x(x +1) + 5(x +1) = (x +1) (6x +5) ∴ zeroes of polynomial equation 6x2 +11x...
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Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively
Solution: (i)1/4, -1 Now formula of quadratic equation is x²-(Sum of root)x + (Product of root) = 0 Plug the value in formula we get x² –(1/4)x -1 = 0 Multiply by 4 to remove denominator...
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If α and β are zeroes of a quadratic polynomial p(x) = rx^2+4x+4, Find the values of “r” if: – α^2 + β^2 = 24.
Solution: From the given polynomial p(x), α + β = −4/r, and αβ = −4/r………. (1) Since,(α + β)2 = α2 + β2 + 2αβ Given, α2 + β2 = 24 and from equation (1). Therefore, (−4/r)2=24+(2×4)/r 16/r2=24+(2×4)/r 16 = 24 r2 + 8r 3r2 + r – 2 = 0 3r2 + 3r...
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If m and n are zeroes of the polynomial 3x^2 + 11x – 4, find the value of m/n + n/m
THANKS BUT I ALSO HAVE SOME OTHER DOUBTS........SO,CAN I ASK IT????
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If m and n are zeroes of the polynomial 3x^2 + 11x – 4, find the value of m/n + n/m
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If m and n are zeroes of the polynomial 3x^2 + 11x – 4, find the value of m/n + n/m
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Find a quadratic polynomial whose sum and product of the zeroes are 21/8 & 5/16 respectively
We have given that sum of zeroes(S)= 21/8 and product of zeroes(P) = 5/16 so the quadratic polynomial p(x)= k(x2 - Sx +P) p(x) = k(x2 - 21/8x + 5/16) where k is any non-zero...
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find the quadratic polynomial each with as the sum and product of its zeroes
please write complete question
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If the graph of a polynomial intersects the x -axis at only one point, can it be a quadratic polynomial?
Yes, because every quadratic polynomial has at the most two zeros.
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