Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution.

Monjur Alahi

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1.


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Salim Ahmed Kawsar

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Answer:

Given that

0.375 Molar aqueous solution

Molar represent molarity of the solution

Hence given molarity of solution will 0.375M

Formula of molarity

Molarity (M) = No. of moles of solute / volume of solution in liter

Volume in liter = 500 ml = 0.5 liter (1000 ml = 1 liter)

Putting the values in above formula we get

 Number of moles = 0.375 × 0.5 = 0.1875 mol

Use formula

Number of moles = mass / molar mass

Molar mass of sodium acetate (CH3COONa) = 82.0245 g mole-1 (Given)

Putting the above values in formula we get

Mass of sodium acetate (CH3COONa) = (82.0245 g mol-1) (0.1875 mole) = 15.38 g

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