If the equations ax^2 + bx + c =0 and x^2 + 2x + 9 =0 have a common root then find a:b:c

This is simple but mind blowing question

Answer 1: Primarily, there are two types of root systems found in plants, namely the tap root system and fibrous root system. The main function of the roots is to absorb...

Pteridophyta do not have  (c) flowers 

Solution: If  a1 /  a2 ≠  b1 /  b2 then the pair of linear equations a1x + b1y + c1 = 0 a2x+ b2y + c2 = 0  has a unique solution. Given pair of  equations K x...

(i) P4 + 5O2 -------> 2P2O5 (ii) 2Al + Fe2O3 -----> Al2O3+ 2Fe (iii) CS2 + 3O2 ------> CO2 + 2SO2 (iv) BaCl2 + ZnSO4 --------> ZnCl2 + BaSO4

(a) Sulphuric acid(aq) + Zinc(s) ------> Zinc  sulphate(aq) + Hydrogen(g) H2SO4(aq) + Zn(s)  -----> ZnSO4(aq) + H2(g) (b) Hydrochloric acid(aq) + Magnesium(s) -----> Magnesiurn chloride(aq) + Hydrogen(g)   2HCl(aq) + Mg(s )   -----> MgCI2(ag) +...

We have seen the following plants: 1. Grass, maize, wheat, chilli, tomato, tulsi, pipal, banyan, mango, jamun, guava, papaya, banana, lemon, sugarcane, potato. Plants having flowers: 2. Maize, wheat, chilli, tomato, tulsi, pipal,...

The given system of equations will have infinitely many solutions if c/6=-1/-2=2/3 which is not possible For no value of c,the given system of equation have infinitely many solutions.

\(\frac{1}{2}\) is a root of quadratic equation. \(\therefore\) It must satisfy the quadratic equation. x2 + kx - \(\frac{5}{4}\) = 0 \(\big(\frac{1}{2}\big)^2\) + k\(\big(\frac{1}{2}\big)\)- \(\frac{5}{4}\) = 0  \(\Rightarrow\) \(\frac{1}{4}\) + \(\frac{k}{2}\)- \(\frac{5}{4}\) = 0 \(\frac{1+2k-5}{4}\) = 0  \(\Rightarrow\) 2k - 4 = 0 \(\Rightarrow\) k = 2