1 Answers
Here one anion replaces another:
Some examples are: Cl 2 + 2 NaBr ⟶ 2 NaCl + Br 2 ↓ {\displaystyle {\ce {Cl2 + 2NaBr -> 2NaCl + Br2}}} Br 2 + 2 KI ⟶ 2 KBr + I 2 ↓ {\displaystyle {\ce {Br2 + 2KI -> 2KBr + I2}}}
Again, the less reactive halogen cannot replace the more reactive halogen:
4 views
Answered