1. It will form a tri-negative ion to acquire stable configuration.
  2. It will form covalent bonds with five atoms of another element.
  3. It will not form compounds with any element.
  4. It will form a tri-positive ion to acquire stable configuration.
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Option 4 : It will form a tri-positive ion to acquire stable configuration.

The correct answer is It will form a tri-positive ion to acquire a stable configuration.

Concept:

Electronic configuration:

  • It can be defined as the distribution of electrons around the nucleus in different energy levels (shells).
  • It was suggested by Bohr and Bury.

Rules for writing the electronic configuration of an atom:​

  • The maximum number of electrons present in a shell is given by the formula 2n2, where ‘n’ is the orbit number or energy level index, 1,2,3, and so on.
  • Hence, the maximum number of electrons in different shells is as follows:
    • The First orbit or K-shell will be = 2 × 12 = 2,
    • The second orbit or L-shell will be = 2 × 22 = 8,
    • The Third orbit or M-shell will be = 2 × 32 = 18,
    • The fourth orbit or N-shell will be= 2 × 42= 32, and so on.
  • The maximum number of electrons that can be accommodated in the outermost orbit is 8.
  • Electrons are not accommodated in a given shell unless the inner shells are filled. That is, the shells are filled in a step-wise manner.

Ions: 

  • An atom or group of atoms that bears one or more positive or negative electrical charges, is called an ion.
  • Cations: Positively charged ions formed by losing electrons. 
  • Anions: Negatively charged ions are formed by gaining electrons.

​Explanation:

  • Element X has 3 electrons in the M shell. 
  • So, its electronic configuration is 2, 8, 3. 
  • An element having less than 4 electrons in its outermost shell tends to lose the electrons to form a cation. 

Thus, It will form a tri-positive ion to acquire a stable configuration.

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