1 Answers

Option 2 : 25 (√3 + 1) 

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⇒ In ΔCDB, ∠CDB = 45°

⇒ Now since, tan 45° = CB/DB = 1

⇒ CB = DB = x

⇒ Now, tan 30° = CB/AB

⇒ 1/√ 3 = x/(50 + x)

⇒ (50 + x) = √3 × x

⇒ 50 = x (√3 – 1)

⇒ x = 50 / (√3 – 1)

⇒ x = 50/(√3 – 1) × (√3 + 1) /(√3 + 1)

⇒ x = 25 (√3 + 1)

∴ Answer is 25 (√3 + 1)

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