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Option 1 : S < A
Given: ‘A ≥ O = T = K > S < Q’
Conclusions:
1.S < A→ True (as A ≥ O > S → S < A)
2. A ≥ S → False (as A ≥ O > S → A > S)
3. O > Q → False (as O > S < Q → hence a clear relation between O & Q cannot be defined)
4. T = Q → False (as T = K > S < Q → hence a clear relation between T & Q cannot be defined)
Clearly, the first expression would be true.
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