1. \(\overline{{(P⊕Q)}} =P⊙Q\)
  2. \(\bar P⊕Q=P⊙Q\)
  3. \(\bar P ⊕\bar Q =P⊕Q\)
  4. \((P⊕\bar P)⊕Q=(P⊙\bar P)⊙\bar Q\)
4 views

1 Answers

Option 4 : \((P⊕\bar P)⊕Q=(P⊙\bar P)⊙\bar Q\)

The correct answer is option 4

Calculation:

LHS = (P ⊕ P̅) ⊕ Q=1 ⊕ Q=Q̅

RHS = (P ⊙ P̅) ⊙ Q̅= 0 ⊙ Q̅ =Q

Hence LHS is not equal to RHS in option 4

4 views

Related Questions