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Option 4 : \((P⊕\bar P)⊕Q=(P⊙\bar P)⊙\bar Q\)
The correct answer is option 4
Calculation:
LHS = (P ⊕ P̅) ⊕ Q=1 ⊕ Q=Q̅
RHS = (P ⊙ P̅) ⊙ Q̅= 0 ⊙ Q̅ =Q
Hence LHS is not equal to RHS in option 4
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