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Option 3 : 32
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N is the midpoint of AD so, area of ∆AMN = ∆NMD
⇒ ∆BMC = 4 and ∆AMN + ∆NMD = 6 + 6 = 12
⇒ So, ∆BMC + ∆AMN + ∆NMD = 16
By the properties of trapezium we know that
⇒ Area of ∆ABM = 1/2 × area of trapezium
So, ∆BMC + ∆AMN + ∆NMD = Area of ∆ABM = 16
⇒ Area of trapezium = 16 + 16 = 32
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