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Option 2 : Either conclusion II or III follows

Statement: S = U > K > L ≥ Y < R ≤ B

Conclusion:

I. K < Y → False (As, S = U > K > L ≥ Y)

II. L > Y → False (As, S = U > K > L ≥ Y)

III. L = Y → False (As, S = U > K > L ≥ Y)

But conclusion II and III forms a complementary pair.

Hence, either conclusion II or III follows.
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