Consider the following data path diagram. Consider an instruction: R0 ← R1 + R2. The following steps are used to execute it over the given data path. Assume that PC is incremented appropriately. The subscripts r and w indicate read and write operations, respectively. 1. R2r, TEMP1f, ALUadd, TEMP2w 2. R1r, TEMP1w 3. PCr, MARw, MEMr 4. TEMP2r, R0w 5. MDRr, IRw Which one of the following is the correct order of execution of the above steps ?

2, 1, 4, 5, 3
1, 2, 4, 3, 5
3, 5, 2, 1, 4
3, 5, 1, 2, 4

LohaHridoy

4 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 3 : 3, 5, 2, 1, 4

Concept:

While executing a micro-instruction such as R0 ← R1 + R2, the CPU performs various micro-operations. Each of this micro-operation is performed in one time cycle.

Execution:

Step 1:

Fetch the instruction. Initially, the address of the instruction to be executed in Program Counter (PC). It is moved from PC to Memory Address Register (MAR). This is done via micro-operation PC_r, MAR_w, MEM_r

Step 2:

Once the instruction has been fetched, in next single time cycle, it is placed into Memory Data Register (MDR) and then to Instruction Register (IR). This is done via micro-operation MDR_r, IR_w

Step 3:

Operand Fetching and Decoding of contents from Register R1 and place it into temporary register Temp₁ via micro- operation R1_r, TEMP1_w

Step 4:

Contents of Register R2 is decoded and ALU performs the addition of fetched content of Temp1 and R2 and place it into Temp2 via micro-operation R2_r, TEMP1_f, ALU_add, TEMP2_w

Step 5:

Finally, the content of Temp₂ is moved into the target register R₀via micro-operation TEMP2_r, R0_w

4 views Answered 2022-09-04 04:29

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