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Option 1 : T < S < C

Let the perimeter of triangle, square and circle be equal to ‘x’ cm

Perimeter of equilateral triangle = 3(side) = x

⇒ Side of equilateral triangle = x/3

⇒ Area of equilateral triangle = (√3/4) × (side)2 = (√3/4) × (x2/9) = x2/12√3

⇒ T ≅ 0.048x2     ...1)

Similarly,

Perimeter of square = 4(side) = x

⇒ Side of square = x/4

⇒ Area of square = (side)2 = x2/16

⇒ S = 0.0625x2     ...2)

Also,

Perimeter of circle = 2π(radius) = x

⇒ Radius of circle = x/2π

⇒ Area of circle = π(radius)2 = π × x2/4π2 = x2/4π

⇒ C ≅ 0.0795x2     ...3)

∴ Comparing equation (1), (2) and (3), we can write, T < S < C
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