1 Answers
Option 1 : 2706 bits
Given:
Message size = 2400 bits.
The header of the transport layer = 150 bits.
Segment size at transport layer = (Header + Message size) = 150 + 2400 = 2550 bits.
Maximum, transmission unit at destination network = 900 bits
So, At a time, data supported by the destination network = 900 – 26 = 876 bits.
Hence, 2550 bits are divided into packets having a maximum of 876 bits. So:
Length of packet 1 = 874 bits.
Length of packet 2 = 874 bits.
Length of packet 3 = 802 bits.
Total = 2550 bits.
Network layer packets are transmitted via two networks, each of which uses a 26-bit header. So, The number of bits, including headers delivered to the destination network is:
Packet 1 (Data + Header) size = 26 + 26 + 874 = 926 bits.
Packet 2 (Data + Header) size = 26 + 26 + 874 = 926 bits.
Packet 3 (Data + Header) size = 26 + 26 + 802 = 854 bits.
Total = 2706 bits.