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Option 2 : B is the CE and reads three newspapers
Four Engineers: H, N, L, and B
Designations: CE, SE, EE, and AE
1) H is the AE.
| Designations | Person | Newspaper Count |
| CE | ||
| SE | ||
| EE | ||
| AE | H |
2) N is not the EE.
3) N is not the CE and he reads more number of newspapers than L.
So, N is the SE.
4) The one who is the CE reads more number of newspapers than L.
Means; L designation is not CE.
So, L is EE.
| Designations | Person | Newspaper Count |
| CE | B | > L |
| SE | N | > L |
| EE | L | |
| AE | H |
5) The person who is the SE reads the maximum number of newspapers.
So, N reads 4 newspapers.
| Designations | Person | Newspaper Count |
| CE | B | > L |
| SE | N | Four |
| EE | L | |
| AE | H |
6) B does not read two newspapers.
| Designations | Person | Newspaper Count |
| CE | B | Three |
| SE | N | Four |
| EE | L | Two |
| AE | H | One |
Hence, "B is the CE and reads three newspapers".
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