1 Answers
Option 4 : Only II
Given:
The maximum mark of B = 150
The maximum marks of A = 120
Concept:
The percentage of gain marks = {(The gain marks)/(The total marks)} × 100
Calculation:
⇒ From the statement l if the highest marks of B is 150 the total highest marks of 6 subjects is 900
⇒ The marks gain by B = (50 + 80 + 60 + 65 + 75 + 35) × (120/100) = 365 × 1.2 = 438
⇒ The total percentage of B = (438/900) × 100 = 48.6̅
⇒ So, the I statement is wrong
⇒ The second statement ll
⇒ if the highest of A is 120 then A will score marks in six subject
⇒ S1 = (90/100) × 120 = 108, S2 = (75/100) × 120 = 90, S3 =(90/100) × 120 = 108, S4 = (80/100) × 120 = 96, S5 = (70/100) × 120 = 84, and S6 = (65/100) × 120 = 78
⇒ Now, there is S1 and S3 has more marks than 105
⇒ So, the statement ll is correct
∴ The required result will be "Only ll".