1 Answers

Option 4 : Only II

Given:

The maximum mark of B = 150

The maximum marks of A = 120

Concept:

The percentage of gain marks = {(The gain marks)/(The total marks)} × 100

Calculation:

⇒ From the statement l if the highest marks of B is 150 the total highest marks of 6 subjects is 900

⇒ The marks gain by B = (50 + 80 + 60 + 65 + 75 + 35) × (120/100) = 365 × 1.2 = 438

⇒ The total percentage of B = (438/900) × 100 = 48.6̅ 

⇒ So, the I statement is wrong

⇒ The second statement ll

⇒ if the highest of A is 120 then A will score marks in six subject 

⇒ S1 = (90/100) × 120 = 108, S2 = (75/100) × 120 = 90, S3 =(90/100) × 120 = 108, S4 = (80/100) × 120 = 96, S5 = (70/100) × 120 = 84, and S6 = (65/100) × 120 = 78

⇒ Now, there is S1 and S3 has more marks than 105

⇒ So, the statement ll is correct 

∴ The required result will be "Only ll".

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