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  1. Is zero
  2. Increases
  3. Decreases whereas the entropy increases
  4. And entropy both decrease
  5. Ice at the base contains impurities which lowers its melting point
  6. Due to the high pressure at the base, its melting point reduces
  7. The iceberg remains in a warmer condition at the base
  8. All of the above
  9. Specific heat
  10. Latent heat of vaporisation
  11. Viscosity
  12. Specific vapor volume
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1 Answers

Answer: Option 3

From second law of thermodynamics $$\eqalign{ & TdS \geqslant \delta Q \cr & \Rightarrow TdS \geqslant dU + \delta W \cr} $$ For an irreversible process $$TdS - dU - \delta W > 0$$ And for a reversible process $$TdS - dU - \delta W = 0$$ For any spontaneous process there should be finite changes so, we can consider it as an irreversible process and we know for irreversible process from second law of thermodynamics by above discussion: $$TdS - dU - PdV > 0$$ Under constant temperature and volume process $$ - dF > 0 \Rightarrow dF Similarly for an constant temperature and pressure process $$d\left( {TS - U - PV} \right) > 0 \Rightarrow dG

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In any spontaneous process,?
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