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Answer: Option 2
$$dU = CvdT - \left[ {P + T\left( {\frac{{\left( {\frac{{\partial V}}{{\partial T}}} \right)P}}{{\left( {\frac{{\partial V}}{{\partial P}}} \right)T}}} \right)dV} \right]$$ Since in case of incompressible fluid $$\eqalign{ & dV = 0 \cr & \Rightarrow dU = {C_V}dT \cr} $$ So, internal energy is a function of temperature only.
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