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Answer: Option 1
Consider an elementary reaction $$A \Leftrightarrow B$$ and let equilibrium concentrations of $$A$$ and $$B$$ be $${{C_a}}$$ and $${{C_b}},$$ So equilibrium constant $$\left( K \right)$$ is $${K_1} = \frac{{{C_b}}}{{{C_a}}}$$ When the concentrations of both the species doubled equilibrium constant becomes $$K = \frac{{2{C_b}}}{{2{C_a}}} \Rightarrow K = {K_1}.$$ Hence remains constant.
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