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Doctors Medicines MCQs Q&A

  1. Reversible isothermal
  2. Irreversible isothermal
  3. Reversible adiabatic
  4. None of these
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1 Answers

Answer: Option 3

Since only for a reversible process we have relation : $$TdS = \delta Q$$ Since for an adiabatic process $$\delta Q = 0$$ $$ \,\,\, \Rightarrow $$ for an reversible adiabatic process $$TdS = 0.$$ So, entropy remains constant. Whereas for an irreversible adiabatic process $$TdS \geqslant 0.$$ Hence entropy goes on increasing for an irreversible adiabatic process.

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