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Answer: Option 2
$$A.$$ solid ⟹ liquid → melting $$B.$$ liquid ⟹ vapor → vaporization $$C.$$ solid ⟹ vapor → sublimation So, enthalpy change for the reaction $${H_2}O\left( {liq} \right) \Rightarrow {H_2}O\left( {gas} \right)$$ is enthalpy change of vaporization. In the question entropy should be replaced by enthalpy.
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