With usual notations the depth of the neutral axis of a balanced section, is given by?

mc/t = (d - n)/n
t/mc = (d - n)/n
t/mc = (d + n)/n
mc/t = n/(d - n)

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 4

5 views Answered 2022-09-01 13:21

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