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The centre of gravity of an isosceles triangle with base (p) and sides (q) from its base is?
$$\frac{{\sqrt {4{{\text{p}}^2} - {{\text{q}}^2}} }}{6}$$
$$\frac{{4{{\text{p}}^2} - {{\text{q}}^2}}}{6}$$
$$\frac{{{{\text{p}}^2} - {{\text{q}}^2}}}{4}$$
$$\frac{{{{\text{p}}^2} + {{\text{q}}^2}}}{4}$$
LohaHridoy
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2025-01-04 04:42
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AhmedNazir
Answer: Option 1
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2022-09-01 13:21
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