- $$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{2{\text{g}}}}$$
- $$\frac{{{{\text{u}}^2}{{\cos }^2}\alpha }}{{2{\text{g}}}}$$
- $$\frac{{{{\text{u}}^2}{{\sin }^2}\alpha }}{{\text{g}}}$$
- $$\frac{{{{\text{u}}^2}{{\cos }^2}\alpha }}{{\text{g}}}$$
1 Answers
4 views
Answered