There are six teachers. Out of them two are primary teachers and two are secondary teachers. They are to stand in a row, so as the primary teachers, middle teachers and secondary teachers are always in a set . The number of ways in which they can do so, is-?

Question

There are six teachers. Out of them two are primary teachers and two are secondary teachers. They are to stand in a row, so as the primary teachers, middle teachers and secondary teachers are always in a set . The number of ways in which they can do so, is-?

52
48
34
None of these

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AhmedNazir · Answer 1 · Sep 01, 2022 13:21:41

Answer: Option 2

There are 2 primary teachers. They can stand in a row in P (2, 2) = 2! = 2 × 1 ways = 2 ways ∴ Two middle teachers. They can stand in a row in P (2, 2) = 2! = 2 × 1 ways = 2 ways There are two secondary teachers. They can stand in a row in P (2, 2) = 2!= 2 × 1 ways = 2 ways These three sets can be arranged themselves in 3! ways = 3 × 2 × 1 = 6 ways Hence,, the required number of ways = 2 × 2 × 2 × 6 = 48 ways

There are six teachers. Out of them two are primary teachers and two are secondary teachers. They are to stand in a row, so as the primary teachers, middle teachers and secondary teachers are always in a set . The number of ways in which they can do so, is-?

1 Answers