The root mean square speed of molecules of a gas is equal to (where, m = mass of the molecule K = Boltzman's constant, T = absolute temperature)?

√(2KT/m)
√(3KT/m)
√(6KT/m)
3KT/m

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 2

empirical relation: Root mean square speed $$ = \sqrt {\frac{{3KT}}{m}} $$ Whereas average velocity $$ = \sqrt {\frac{{8KT}}{{\pi m}}} $$

5 views Answered 2022-09-01 13:21

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