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Doctors Medicines MCQs Q&A

  1. (∂P/∂V)S = (∂P/∂V)T
  2. (∂P/∂V)S = [(∂P/∂V)T]Y
  3. (∂P/∂V)S = y(∂P/∂V)T
  4. (∂P/∂V)S = 1/y(∂P/∂V)T
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1 Answers

Answer: Option 3

For an adiabatic process → $$P{V^y}$$ = constant For an isothermal process → $$PV$$ = constant So, slope for adiabatic process in $$PV$$ plane is $$\frac{{dp}}{{dv}} = - y\frac{p}{v}$$ Slope for isothermal process is $$\frac{{dp}}{{dv}} = - \frac{p}{v}$$ Hence, $${\left( {\frac{{\partial p}}{{\partial v}}} \right)_S} = - y{\left( {\frac{{\partial p}}{{\partial v}}} \right)_T}$$

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