The torque transmitted by a solid shaft of diameter (D) is (where $$\tau $$ = Maximum allowable shear stress)?

$$\frac{\pi }{4} \times \tau \times {{\text{D}}^3}$$
$$\frac{\pi }{{16}} \times \tau \times {{\text{D}}^3}$$
$$\frac{\pi }{{32}} \times \tau \times {{\text{D}}^3}$$
$$\frac{\pi }{{64}} \times \tau \times {{\text{D}}^3}$$

LohaHridoy

6 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 2

Let'

6 views Answered 2022-09-01 13:21

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