The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, $$\omega $$ = Angular speed of crank, r = Radius of crank, $$\theta $$ = Angle of inclination of crank with the line of stroke and n = Ratio of the length of connecting rod to radius of crank)?

$${\text{m}}{\omega ^2}{\text{r}}\sin \theta $$
$${\text{m}}{\omega ^2}{\text{r}}\cos \theta $$
$${\text{m}}{\omega ^2}{\text{r}}\frac{{\sin 2\theta }}{{\text{n}}}$$
$${\text{m}}{\omega ^2}{\text{r}}\frac{{\cos2\theta }}{{\text{n}}}$$

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 2

Let'

5 views Answered 2022-09-01 13:21

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